-16x^2+320x+24000=0

Solution for -16x^2+320x+24000=0 equation:

-16x^2+320x+24000=0

a = -16; b = 320; c = +24000;
Δ = b2-4ac
Δ = 3202-4·(-16)·24000
Δ = 1638400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1638400}=1280$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(320)-1280}{2*-16}=\frac{-1600}{-32}
=+50
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(320)+1280}{2*-16}=\frac{960}{-32}
=-30
$